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1990 Calder Cup Playoffs

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The 1990 Calder Cup Playoffs of the American Hockey League began on April 4, 1990.[1] The eight teams that qualified, four from each division, played best-of-7 series for Division Semifinals and Division Finals. The division champions played a best-of-7 series for the Calder Cup. The Calder Cup Final ended on May 18, 1990 with the Springfield Indians defeating the Rochester Americans four games to two to win the Calder Cup for the sixth time in team history.[2] Despite an injury preventing him from playing in the final game, Springfield goaltender Jeff Hackett won the Jack A. Butterfield Trophy as the MVP of the playoffs.[3]

The league instituted trophies for division champions in the playoffs; the Richard F. Canning Trophy in the North Division, and the Robert W. Clarke Trophy in the South Division.[4][5]

Playoff seedsEdit

After the 1989-90 AHL regular season, the top four teams from each division qualified for the playoffs. The Sherbrooke Canadiens finished the regular season with the best overall record for the second straight season.[6]

Northern DivisionEdit

  1. Sherbrooke Canadiens - 102 points
  2. Cape Breton Oilers - 85 points
  3. Springfield Indians - 80 points
  4. Halifax Citadels - 80 points

Southern DivisionEdit

  1. Rochester Americans - 95 points
  2. Adirondack Red Wings - 95 points
  3. Baltimore Skipjacks - 93 points
  4. Utica Devils - 92 points

BracketEdit

  Division Semifinals Division Finals Calder Cup Final
                           
  1  Sherbrooke 4  
4  Halifax 2  
  1  Sherbrooke 2  
Northern Division
  3  Springfield 4  
2  Cape Breton 2
  3  Springfield 4  
    N3  Springfield 4
  S1  Rochester 2
  1  Rochester 4  
4  Utica 1  
1  Rochester 4
Southern Division
  3  Baltimore 2  
2  Adirondack 2
  3  Baltimore 4  

In each round, the team that earned more points during the regular season receives home ice advantage, meaning they receive the "extra" game on home-ice if the series reaches the maximum number of games. There is no set series format due to arena scheduling conflicts and travel considerations.[7]

Division Semifinals Edit

Note: Home team is listed first.

Northern DivisionEdit

(1) Sherbrooke Canadiens vs. (4) Halifax Citadels Edit

Sherbrooke won series 4 – 2


(2) Cape Breton Oilers vs. (3) Springfield Indians Edit

Springfield won series 4 - 2


Southern DivisionEdit

(1) Rochester Americans vs. (4) Utica Devils Edit

Rochester won series 4 - 1


(2) Adirondack Red Wings vs. (3) Baltimore Skipjacks Edit

Baltimore won series 4 - 2


Division FinalsEdit

Northern DivisionEdit

(1) Sherbrooke Canadiens vs. (3) Springfield IndiansEdit

Springfield won series 4 - 2


Southern DivisionEdit

(1) Rochester Americans vs. (3) Baltimore SkipjacksEdit

Rochester won series 4 - 2


Calder Cup FinalEdit

(S1) Rochester Americans vs. (N3) Springfield IndiansEdit

Springfield won series 4 - 2


See alsoEdit

ReferencesEdit

  1. 1990 AHL playoff results The Internet Hockey Database. Retrieved on May 5, 2008.
  2. Calder Cup champions caldercup.com. Retrieved on May 5, 2008.
  3. Jack A. Butterfield Trophy ahlhalloffame.com. Retrieved on May 6, 2008.
  4. Richard F. Canning Trophy ahlhalloffame.com. Retrieved on May 6, 2008.
  5. Robert W. Clarke Trophy ahlhalloffame.com. Retrieved on May 6, 2008.
  6. 1989-90 AHL standings The Internet Hockey Database. Retrieved on May 5, 2008.
  7. Frequently asked questions theahl.com. Retrieved on May 12, 2008.
Preceded by
1989 Calder Cup Playoffs
Calder Cup Playoffs
1990
Succeeded by
1991 Calder Cup Playoffs
This page uses content from Wikipedia. The original article was at 1990 Calder Cup Playoffs. The list of authors can be seen in the page history. As with Ice Hockey Wiki, the text of Wikipedia is available under the Creative Commons Attribution-Share Alike License 3.0 (Unported) (CC-BY-SA).


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